Python Program to Check Leap Year | Leap Year Program in Python

In this Python tutorial, you will learn how to write a python program to check a leap year. Here in this article we have provided a python source code which output if the user entered year is a leap year or not.

Prerequisite To Leap Year Program in Python

• Python Input, Output
• Python nested if…else statement
• Python Data types
• Python Arithmetic Operators

Steps

• First, we ask the user to enter the 4 digit year.
• Using the int() function we will convert the entered string into an integer value.
• Using the if....elif nested statement and arithmetic modules operator we check for conditions.

Leap Year Program in Python

Python Code

year = int(input("Enter the Year: "))
if year%4==0:
    if year%100==0:
        if year%400==0:
            print(year, "is a leap year")
        else:
            print(year, "is a not leap year")
    else:
        print(year, "is a leap year")
else:
    print(year, "is a not leap year")

Output 1:

Enter the Year: 2020
2020 is a leap year

Output 2:

Enter the Year: 2019
2019 is a not leap year

Conclusion

Here in this tutorial, you learned how to write a python program to check if the user entered Year is a leap year or not. In the first check, we check if the year is divisible by 4. If the Year is divisible by 4 and not divisible by 100 then it is a leap year. If a Year is divisible by 4 and 100, it has to be divisible by 400 to be a leap year.

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