Program to Check Whether the Year is a Leap or Not [C, C++, Python & Java]

This tutorial will help you learn to write a program in C, C++, Python, and Java to check whether a year is a leap or not.

To write the program, you must know the logic to determine a leap year, the if...else statement, and the programming syntax.

So, let us begin!

What is a Leap Year?

A leap year is a year that consists of an extra day in a year, i.e., 366 days. The extra day is added to the shortest month, i.e., February. So, whenever a leap year comes, the month of February has 29 days. It occurs after every four years.

The major reason to add 1 extra day after every four years is to maintain the calendar year synchronized with the astronomical year or seasonal year.

There are some conditions to be a leap year, as follows:

• The year should be a multiple of 400.
• The year should be a multiple of 4 and not 100.

C Program to Check Whether the Year is a Leap or Not

#include<stdio.h>
int main()
{
   int y;
   printf("Enter any year: ");
   scanf("%d", &y);
   
   if (y % 4 == 0)
   {
       if (y % 100 == 0)
       {
           if (y % 400 == 0)
           {
               printf("It is a leap year");
           }
           else
           {
               printf("It is not a leap year");
           }
       }
       else
       {
           printf("It is a leap year");
       }
   }
   else
   {
       printf("It is not a leap year");
   }
   
   return 0;
}

Output

Enter any year: 4500
It is not a leap year

C++ Program to Check Whether the Year is a Leap or Not

#include<iostream>
using namespace std;

int main()
{
   int y;
   cout<<"Enter any year: ";
   cin>>y;
   
   if (y % 4 == 0)
   {
       if (y % 100 == 0)
       {
           if (y % 400 == 0)
           {
               cout<<"It is a leap year";
           }
           else
           {
               cout<<"It is not a leap year";
           }
       }
       else
       {
           cout<<"It is a leap year";
       }
   }
   else
   {
       cout<<"It is not a leap year";
   }
   
   return 0;
}

Output

Enter any year: 5000
It is a leap year

Python Program to Check Whether the Year is a Leap or Not

y= int(input("Enter any year: "))
if y%4==0:
    if y%100:
        if y%400==0:
            print("It is a leap year")
        else:
            print("It is not a leap year")
    else:
        print("It is a leap year")
else:
    print("It is not a leap year")

Output

Enter any year: 2019
It is not a leap year

Java Program to Check Whether the Year is a Leap or Not

import java.util.Scanner;
public class Main
{
    public static void main(String[] args)
    {
        int y;
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter any year: ");
        y = sc.nextInt();
        if (y % 4 == 0)
        {
            if (y % 100 == 0)
            {
                if (y % 400 == 0)
                {
                    System.out.println("It is a leap year");
                }
                else
                {
                    System.out.println("It is not a leap year");
                }
            }
            else
            {
                System.out.println("It is a leap year");
            }
        }
        else
        {
            System.out.println("It is not a leap year");
        }
    }
}

Output

Enter any year: 
2004
It is a leap year

Conclusion

You might have got an idea of how to write a program in C, C++, Python, and Java to check whether a year is a leap or not. The only thing you need to take care of is the logic to determine the leap year. The correct use of if...else statements play a vital role here. Understand the flow of the program and implement it on your system.

Good luck!

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